
Patrick B. answered 03/09/19
Math and computer tutor/teacher
The first one factors as (x+3)(x+3) = 0
So x=-3 is a zero of multiplicity 2
The second one factors as (x^2) (x^2 + 4x - 21)
x^2( x + 7 )( x - 3 )
The zeros are x=0 of multiplicity 2, x=-7 and x=3