Find all zeros of the function: t ( x ) = 9 x 2 − 36 x + 32 .

Answer 1

9x^2 - 36x + 32

= ( 3x - 8 )(3x - 4 )

the solutions are 8/3 and 4/3

check:

9(8/3)^2 - 36(8/3) + 32 =

9(64/9) - 36(8/3) + 32 =

64 - 96 + 32 = 0

check of x=4/3 is left for you, but it checks!