Patrick B. answered 03/11/19
Math and computer tutor/teacher
a) 5(x-24)(x-22)
b) y = kx(x-13)
22 = k(2)(-11)
k = -1
y = -x(x-13)
c) y = k(x-4)(x-8)
12 = k(32) when x=0
12/32 = k
3/8 = k
y = (3/8)(x-4)(x-8)
Rachel J.
asked 03/06/19a. a=5; x-intercepts of graph are 24 and 22
b. x-intercepts of graph are 0 and 13; graph contains point (2,22)
c. x-intercepts of graph is 4 and 8; y-intercept is 12
Patrick B. answered 03/11/19
Math and computer tutor/teacher
a) 5(x-24)(x-22)
b) y = kx(x-13)
22 = k(2)(-11)
k = -1
y = -x(x-13)
c) y = k(x-4)(x-8)
12 = k(32) when x=0
12/32 = k
3/8 = k
y = (3/8)(x-4)(x-8)
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