In chemistry the volume for a certain gas is given by V = 10T, where V is measured in cc and T is temperature in °C. If the temperature varies from 90°C to 130°C, find the set of volume values.

Answer 1

Assuming pressure is constant, then V₁/T₁ = V₂/T₂ but T in this equation must be in Kelvin so to use ºC we need to modify it to read V₁/(T₁+273.15) = V₂/(T₂+273.15). As long as both V₁ and V₂ are in cc's, the equation will work just fine (no need to convert anything there). But we know that V₁ = 10T₁ so we can put that into the equation. It becomes:

10T₁/(T₁+273.15) = V₂/(T₂+273.15)

Solving for V₂ we get:

V₂ = 10T₁(T₂+273.15)/(T₁+273.15) = 10(90)(130+273.15)/(90+273.15) = 999.13 cc

And V1 = 10(90) = 900 cc