Write an equation in intercept form of the parabola that passes through the point (1,32) and has x-intercepts −7 and 3.

Answer 1

y = k*(x+7)(x-3)

y = k *(x^2 + 4x - 21)

32 = k ( 8 * -2)

32 = -16* k

k = 32/-16 = -2

y = -2(x+7)(x-3)

= -2(x^2 + 4x - 21)

= -2(x^2 +4x ) -42

= 2(x^2 + 4x + 4) - 42 - 8

= 2 (x+2)^2 -50