What would the points be on a graph for y=1/3×-1 and -2x+y=-6

Question

What would the points be on a graph for y=1/3×-1 and -2x+y=-6. I know the point of intersection but i need to plot

Answer 1

graphing when the equation in y=mx+b form is easy. start with the b (y-intercept) and graph that point on the y-axis. then think of the coefficient of the x as "rise over run" from the point you just graphed.

y = 1/3x - 1

mark the point at -1 on the y-axis. this is the same as (0, -1). now use the slope to get another point. rise 1, run 3. in other words, from (0, -1), move up (in the y direction) 1, then move to the right (positive x direction) 3. color in that point...it should be (3, 0). draw a line thru the points, extending beyond the points, and put arrow heads on either end.

-2x + y = -6

this would be easy if in y=mx+b form, so we can manipulate it to look that way.

to get rid of -2x on the left side, add 2x to both sides.

the new equation is y = 2x - 6

as above, go to -6 on the y-axis (0, -6) and color it in. now you need to use the slope of 2 to find another point on the line. since you want a rise and a run, rewrite 2 as 2/1. now put your pencil on your first point of (0, -6). rise 2 (up 2), run 1 (to the right 1). color that point...should be (1, -4). draw a line thru your two points and put arrow heads on the ends.