Since the leading exponents are equal, the horizontal asymtote is at y = 6/3, or y = 2.
To find the vertical asymtote, we set the denominator equal to 0 and solve.
3x2 -5x - 8 = 0
(3x - 8)(x + 1) = 0
3x - 8 = 0
3x = 8
x = 8/3
x + 1 = 0
x = -1
Now, to simplify. The numerator factors to (3x - 8)(2x + 9). 3x - 8 cancels out with the same in the denominator, so we are left with...
(2x + 9)/(x + 1)
Because 3x - 8 cancels out, we are left with a vertical asymptote at x = -1 and a hole at x = 8/3.