if x^2+y^2=25 find the value dy/dx at the point (3, 4).

Question

if x^2+y^2=25 find the value dy/dx at the point (3, 4).

Answer 1

if x^2+y^2=25 find the value dy/dx at the point (3, 4).

X² + Y²=25,

Or,2x +2y.(dy/dx)=0

Or,2x +2y.(dy/dx)=0

Or,dy/dx=-(x/y)

Or,dy/dx(at x=3 & y=4)=-(x/y)

Or,dy/dx= -(3/4)