perpendicular to the line y=4x-3 passing through (-16,5) write the equation of line in slope intercept form and the ordered pair that is the y-intercept

Answer 1

Greetings! Lets solve this shall we ?

So, we must find the equation of a line perpendicular to the given line and point such that,

we take the given slope and take the reciprocal of it such that m is now -1/4 and we pull out the point slope formula such that

y - y1 = m(x - x1)

y - 5 = -1/4(x - (-16))

y - 5 = -1/4(x + 16)..............Distribute the -1/4 inside such that

y - 5 = -1/4x - 4............then add 5 such that

y = (-1/4)x + 1

I hope this helped!