f(x) = 2x + 1
g(x) = 2x2 + 1
Set f(x) = g(x) ⇒ 2x + 1 = 2x2 + 1
We want to rewrite the equation in quadratic form. Then factor it using GCF (greatest common factor). Apply Zero Product Property to set both factors equal to 0 to find x.
2x2 - 2x = 0 ⇒ 2x(x - 1) = 0 ⇒ 2x = 0 or x -1 = 0 ⇒ x = 0 or x = 1
Plug in the x values to find y in order to create the solution points for the system of equations.
f(0) = 2(0) + 1 = 0 + 1 = 1
f(1) = 2(1) + 1 = 2 + 1 = 3
g(0) = 2(0)2 + 1 = 2(0) + 1 = 0 + 1 = 1
g(1) = 2(1)2 + 1 = 2(1) + 1 = 2 + 1 = 3
The solution points are (0, 1) and (1, 3). These are the intersection points of the two equations.
Lets see if x =3, then we have:
f(3) = 2(3) + 1 = 6 + 1 = 7
g(3) = 2(3)2 + 1 = 2(9) + 1 = 18 + 1 = 19
f(3) ≠ g(3) ⇒ 7 ≠ 19
3 is not part of the solution to the system of equations.