1/x-3+2/x-2=8/x solve by factorisation

Answer 1

First of all, you need to be clear about your problem; writing fractions in this editor is sometimes a challenge.

I assume you mean: [1/(x-3)]+[2/(x-2)]=8/x

Add the left side: (3x-8)/[(x-3)(x-2)]=8/x

Now cross multiply:x(3x-8)=8x²-40x+48

Collect terms: 5x²-32x+48=0

Factor: (5x-12)(x-4)=0