Joshua T. answered 16d
Highly Experienced Math Tutor — Fresh, Effective, Student-Focused
This is an exponential growth word problem. Let's first look at the Exponential Growth Formula.
Step 0: Exponential Growth Formula
P(t) = Aekt
'A' is the initial population, 'e' is the Euler constant, 'k' is the growth constant, 't' is the time, and 'P(t)' is the population at time 't'.
Step 1: Definitions
We are told that initially, "research scientists released 500 turtles into a wetland". That means we can define 'A', the initial population.
A = 500
We are also told that "After 5 years, the research team estimated that the population had grown to 929 turtles." That means we can define 't' and 'P(t)'.
t = 5, P(5) = 929
Step 2: Substitute Into Population Equation
P(t) = Aekt
P(5) = 500e5k
929 = 500e5k
Note that the only variable that we don't know is 'k', the growth constant. Let's use algebra to solve for it.
Step 3: Solving For the Growth Constant
Let's divide both sides of the equation by 500.
929 / 500 = 500 e5k / 500
929 / 500 = e5k
Let's take the natural log of both sides of the equation.
ln(929 / 500) = ln(e5k)
ln(929 / 500) = 5k
Let's divide both sides of the equation by 5.
ln(929 / 500) / 5 = 5k / 5
ln(929 / 500) / 5 = k
Putting this in a calculator, we get a value for 'k'.
k = 0.1239
Step 4: Population Function
Now that we have k, we can write a complete population function for the turtles.
P(t) = Aekt
P(t) = 500e0.1239t
Step 5: Population Prediction
We are asked to "predict the population of turtles after 10 years." This means that we know a value for the time 't'.
t = 10
Let's substitute t = 10 into our new population equation.
P(t) = 500e0.1239t
P(10) = 500e0.1239 * 10
Putting this in a calculator, we get a value for P(10).
P(10) = 1726.082
There are approximately 1,726 turtles after 10 years.