The length of a rectangle is equal to 4 times the width plus 3 feet. If the area of the rectangle is 52 square feet, what are the dimension of the rectangle?

Answer 1

L = 4w+3

Area = length x width

52 = (4w+3)* w = w(4w+3) = 4w^2 + 3w

4w^2 + 3w - 52 = 0

( 4w - 13 )(w + 4 ) = 0

w+4=0 results in negative measures

4w - 13 = 0 ---> w = 13/4

length = (13/4)(4) + 3 = 13+3 = 16