Joseph A. answered 01/22/19
Experienced Math and Test Prep Tutor
Hi Megan,
The answer is 120. Here's how I solved it:
You have to create a 3-digit passcode, like so: _ _ _
Now, the first digit has to be an odd number. There are 4 odd digits: 1,3,5, and 7.
So there are 4 choices for the first digit: 4 _ _
The next digit can be any of the digits EXCEPT it can't be the same as the one you just selected. So there are 7 - 1 = 6 digits that can be placed into the second position: 4 6 _
Finally, the last digit. Since you can't repeat a digit, the last place can be any digit you didn't pick in the first two positions, so there are 7 - 2 = 5 digits available: 4 6 5. We multiply these together to get 4*6*5 = 120 possible combinations.
Hope this helped!