h(t)=-16t^2 +64t

Question

A baseball bounces off of the ground. The height of the ball "h" feet above the ground after "t" seconds is modeled by the function h(t)=-16t^2 +64t. How many seconds will it take for the ball to touch the ground again?

Answer 1

h(t) = -16t² + 64t = -16t(t-4)

The height of the ball when it's on the ground is 0:

0 = -16t(t-4)

Apply the Zero Factor Property to solve for t. There are two values. Units are seconds