Niral P. answered • 01/18/19
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Good question!
For this question, we have to determine what g(x+a) and g(x) are.
Plug in (x+a) for x in the original function...
g(x+a) = 4 * (x+a)^2 + 2 * (x+a)
=4 (x^2 + 2ax + a^2) + 2x + 2a
= 4x^2 + 8ax + 4 a^2 + 2x + 2a
And we know that...
g(x) = 4x^2 + 2x
So...
g(x+a) - g(x) = ( 4x^2 + 8ax + 4 a^2 + 2x + 2a) - (4x^2 + 2x)
= 4a^2 + 8ax + 2a
Hope that helps!
Niral P.
I'm not entirely certain what you did, but where did the ax^2 term come from? Additionally, the 2x's cancel as the function g(x) is subtracted, and the negative must be distributed.
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06/30/20
Michelle S.
the answer would be 8ax^2+4x+4a^2+2a, the 2x's wouldnt cancel out because theyre the same so they would add to 4x.06/30/20