James L. answered 04/21/15
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Tutoring for AP and IB Physics and SAT Math
This one is tricky, cause you have to use the half-life to find the decay constant as follows.
First we know that this equation describes the situation:
R = R0e-(t/λ), where R is the decay rate at time t and R0 is the decay rate at the time of eruption. λ is the decay constant which we have to figure using the half life. To do this we make R = R0/2 and plug it in, getting 1/2 = e-τ/λ with the greek tau in the numerator equal to the half life. Here is where it gets tricky:
1/2 = 1/eτ/λ and if you take the reciprocal you get
2 = eτ/λ
Now take ln of both sides and you get ln 2 = τ/λ and using the info from the problem we see that the decay constant is 5715/(ln 2) = 8245.
Now we are in a position to solve by graphing y = e-t/8245. Using a graphing calculator we find that when y = 0.62, t = 3900, so the eruption took place that number of years prior to 2015. As a check when y = 0.5 (the half life amount) t = 5700 as it must