Dimension Problem

Question

The length of a rectangle is six times its width.
If the area of the rectangle is
600

cm2
, find its perimeter.

Answer 1

 

Perimeter (P) of rectangle = 2(w+l)

 

First we will calculate the individual values for the width and length of the rectangle using the value for the Area and the fact that the length is six times the width

A=600 cm²

 

l=6*w

 

Area (A) of rectangle = width (w) x length (l). In this case the Area = width x 6width

 

600=w*6w

 

600=6w²

 

w²=600/6

 

w² =100

 

(take the square root of both sides)

w=10

 

plugging this number for width back into the original Area formula gives us 60 for length. 

 

Therefore, the perimeter is

Perimeter (P) of rectangle = 2(w+l)

 

P=2(10+60)

 

P=2(70)

 

P=140