A ball is thrown up in the air with an initial velocity of 64 ft/sec. What is the maximum height the ball will reach?

Question

The question also comes with the equation h = -16t² + 64t.

Answer 1

The equation of motion is 64t-16t² (assuming the initial height is 0).

The maximum height will occur when 32t=64 (the derivative set equal to 0), i.e. when t=2 and height=64