With real coefficients, the Conjugate Root Theorem tells us that if 3i is a root, so is -3i. Hence the polynomial has three roots: 4, 3i, and -3i. Use the factored form:
f(x) = a·(x-p)(x-q)(x-r)
- a = leading coefficient = -1
- p = one zero = 4
- q = the second zero = 3i
- r = the last zero = -3i
f(x) = -1·(x-4)(x-3i)(x-(-3i))
f(x) = -(x-4)(x-3i)(x+3i)
Multiply it out to put it into standard form.