J.R. S. answered • 12/27/18
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
Look at the correctly balanced equation:
2 Zn(s) + O2(g) ==> 2 ZnO
Assuming the question is asking about 17.5 GRAMS of ZnO (and not 17.5 moles or anything else), then...
17.5 g ZnO x 81.4 g/mole x 1 mole O2/2 moles ZnO x 32 g O2/mole = 3.44 g O2 needed (assuming sufficient Zn is present)
J.R. S.
tutor
What is this comment supposed to add to the discussion? It is simply a reiteration of what was stated in the original answer.
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12/27/18
Ismana S.
Assuming the question is asking about 17.5 GRAMS of ZnO (and not 17.5 moles or anything else), then... 17.5 g ZnO x 81.4 g/mole x 1 mole O2/2 moles ZnO x 32 g O2/mole = 3.44 g O2 needed (assuming sufficient Zn is present)12/27/18