Arthur D. answered 10/28/14
Tutor
5.0
(255)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
d=rt
x=shorter segment
x+96=longer segment
x=60t and x+96=120t so t=x/60 and t=(x+96)/120
find the total time for the trip...
(x/60)+[(x+96)/120]=total time
simplifying...
(2x/120)+[(x+96)/120]=(3x+96)/120 for the total time
total distance=average rate*total time
(x+x+96)=100*(3x+96)/120
2x+96=5*(3x+96)/6 (simplified the right side)
multiply both sides by 6
12x+576=5(3x+96)
12x+576=15x+480
15x-12x=576-480
3x=96
x=96/3
x=32 km for the shorter distance
x+96=128 km for the longer distance
128 km+ 32 km=160 km
the cities are 160 km apart
check; d=rt
160=100t
160/100=t
1.6 hours is the time
32=60t, 32/60=t
128=120t, 128/120=t
32/60+128/120=64/120+128/120=192/120=1.6 hours again for the total time