If the cubic equation has REAL coefficients, then it must have at least 1 real root.
If it has only one real root, then the other 2 roots are complex conjugates.
Otherwise it must have 3 real roots.
Olivia G.
asked 12/11/18Is it possible for a cubic function to have 2 real and 1 imaginary solution and why?
If the cubic equation has REAL coefficients, then it must have at least 1 real root.
If it has only one real root, then the other 2 roots are complex conjugates.
Otherwise it must have 3 real roots.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.