Dimension Problem

Question

The area of a rectangle is
52 ft2
, and the length of the rectangle is
5 ft
less than twice the width. Find the dimensions of the rectangle.

Answer 1

A= length times width = 52. width can just be w (because there is no information about it). Length is 5 less than 2w...

So if w = 10, length is 15 (2 times 10 is 20 and 5 less is 15).

If w = 15, length is 25 (2 times 15 is 30 and 5 less is 25).  Does that help write an equation/expression for Length?

 

52 = w times (your expression for length). 

You will have to use the Distributive property; and your equation will be a quadratic. From there factor or use the quadratic formula to solve....