A number is 11 more than another number. Twice the sum of the two numbers is 6. Find the two numbers.

Answer 1

first number = n

second number = n+11

2(n+n+11)= 6

2(2n+11)=6

4n+22 =6

4n = -16

n=-4

first number = n =-4

second number = n+11=-4+11=7

Answer 2

The numbers are

n and n + 11

2(n + n +11) = 6

Can you solve for n and answer?

Answer 3