Finite Help!!!!!!!

Question

This problem involves inspection at a widget factory. Assume that a box contains 6 defective widgets and 13 acceptable widgets. There are 3 inspectors, each of whom selects a widget from the box at random, inspects it, and then replaces it in the box. Each inspector makes his or her inspection at a different time. What is the probability that at least one inspector will find a defective widget?

Answer 1

Figure the probability that none of the inspectors find a defective widget and 1 minus that probability is the probability at least one of them did. Since each is replacing the widget in the box after inspecting it (whether it was defective or not), each has a 13/19 or roughly 0.684 chance that they choose an acceptable widget. So the chance all 3 choose an acceptable widget would be that chance cubed or roughly 0.32. So, the chance at least one found a defective widget would be roughly 0.68.