Taige Z.

asked • 11/27/18

One earthquake has MMS magnitude 3.3. If a second earthquake has 610 times as much energy (earth movement) as the first, find the magnitude of the second quake.

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Lauren H. answered • 11/27/18

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log(610) = 2.8

3.3 + 2.8 = 6.1

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Cole D.

This isn't true. Instead, you must use the formula M = 2/3log(S/S_0), where M is the first earthquake's magnitude and S is the seismic moment. In this case... 3.3 = 2/3log(S/S_0) 3.3(2/3) = log(S/S_0) 4.95 = log(S_S_0) 10^4.95 = S/S_0 S = 10^4.95*S_0 S = 610*10^4.95*S_0 M = 2/3log((610*10^4.95*S_0)/S_0) M = 2/3log(60*10^4.95) M = 5.156887 Therefore, the second quake's magnitude is 5.156887
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05/13/20

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