
Philip P. answered 11/27/18
Affordable, Experienced, and Patient Algebra Tutor
If it's a geometric sequence, then the ratio of successive terms are equal (the common ratio). That is:
(x+3)/x = x/(x-2)
(x+3)(x-2) = x2
x2 + x - 6 = x2
Solve for x
Rogerio J.
asked 11/27/18Let x-2, x, x+3 be the first 3 terms of a geometric sequence. Find the value of x..
Please help, been trying to do this for hours and cant come uyp with a good answer, any help would be extremely appreaciated, thanks!
Philip P. answered 11/27/18
Affordable, Experienced, and Patient Algebra Tutor
If it's a geometric sequence, then the ratio of successive terms are equal (the common ratio). That is:
(x+3)/x = x/(x-2)
(x+3)(x-2) = x2
x2 + x - 6 = x2
Solve for x
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