Each spring, a 12 meter by 12 meter garden has its length increased by 2 meters but its width decreased by 50 centimeters. What will be the maximum attainable area of the garden?

Question

Paul M. · Accepted Answer

A = (12 + 2k)(12 - 0.5k)Find the derivative of A with respect to k and set it = 0.The maximum area will be where the derivative = 0.

Each spring, a 12 meter by 12 meter garden has its length increased by 2 meters but its width decreased by 50 centimeters. What will be the maximum attainable area of the garden?

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In the equation 3x+2y=9, if x increases by 2 then y does what?

-sin^2=2cosx-2

3^(2x)+28=11(3^x)

The focus of a parabola has coordinates (0,-3/10) and the vertex at the origin. Find the equations of the directrix, the axis of symmetry, and the parabola.

y=(x^2-x-2)/(x^2-16)

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Each spring, a 12 meter by 12 meter garden has its length increased by 2 meters but its width decreased by 50 centimeters. What will be the maximum attainable area of the garden?

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

In the equation 3x+2y=9, if x increases by 2 then y does what?

-sin^2=2cosx-2

3^(2x)+28=11(3^x)

The focus of a parabola has coordinates (0,-3/10) and the vertex at the origin. Find the equations of the directrix, the axis of symmetry, and the parabola.

y=(x^2-x-2)/(x^2-16)

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