How many years would it take an amount of money to double if it is invested at 10% compounded continuously

Question

choices

2 In2

20 In 2

5 In2

10 In 2

In2

25 In2

Answer 1

A = Pe^rt

1. A = 2P (double our initial investment P)
2. r = 10% = 0.10

2P = Pe^0.10t

2 = e^0.10t

ln(2) = 0.10t

Solve for t.