Gwenn C.
asked • 11/05/18determine the equation given its zeros
determine the quadratic equation given the zeros of a quadratic function:
x= ( 2 ± √13 / 5)
More
1 Expert Answer
Arturo O. answered • 11/05/18
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
You have two zeroes x1 and x2. The equation is
f(x) = A(x - x1)(x - x2)
where A is any real number other than zero. Plug in x1 and x2, and pick a convenient number for A, such as A = 1.
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Samuel B.
I'm assuming you mean x= ( (2 ± √13) / 5). If so, you know that b = -2 since x = (-b ± √(b^2 - 4ac))/2a, and -b = 2. Also, 2a = 5, so a = 2.5 a = 2.5, b = -2, so (13 = b^2 - 4ac), so 13 = 4 - 4(2.5)c --> -9 = 10c, c = -0.9 so, a = 2.5, b = -2, c = -0.9 so x = (2 ± √((-2)^2 - 4(2.5)(-0.9)))/2(2.5)11/05/18