Part 1
Event A = bowl x, P(A) = 1/3
Event B = blue(1/3)[(2/5) + (2/5) + (1/4)] = 7/20
Event A and B = blue form bowl x = 2/15
P(A|B) = P(A and B)/P(B) = (2/15)/7/20 = 8/21
Part 2 works in the same way!
Katie G.
asked 11/05/18Rework problem 7 from section 3.4 of your text, involving the selection of a colored ball from one of three bowls. Assume that you randomly pick one of the bowls: X, Y, or Z. You then randomly draw one ball out of the selected bowl and note its color. The bowls contain the following colored balls:
Bowl X: 1 red, 2 white, and 2 blue.
Bowl Y: 2 red, 1 white, and 2 blue.
Bowl Z: 2 red, 1 white, and 1 blue.
(1) If the ball is blue, what is the probability that it was drawn from bowl X?
(2) If the ball is either blue or white, what is the probability that it was drawn from bowl Y?
Part 1
Event A = bowl x, P(A) = 1/3
Event B = blue(1/3)[(2/5) + (2/5) + (1/4)] = 7/20
Event A and B = blue form bowl x = 2/15
P(A|B) = P(A and B)/P(B) = (2/15)/7/20 = 8/21
Part 2 works in the same way!
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