Find the equation of the line that passes through the point (-2, 5) and is perpendicular to the line x + 3y = 4.

Question

Find the equation of the line that passes through the point (-2, 5) and is perpendicular to the line x + 3y = 4. 

Answer 1

Put the equation into slope intercept form: y = -(1/3)x + (4/3)

The slope of the line perpendicular to this line is 3 (negative reciprocal of the slope of the given line).

The equation of the line with slope 3 and through (-2,5) is

3 = (y - 5)/(x + 2)

You can massage this form of the equation into whatever form you need.