Find the values of p such that the equation px^2 - 2x + 3 = 0 has two different real roots

Answer 1

The discriminant of Ax² + Bx + C is B² - 4AC.

The equation Ax² + Bx + C = 0 has 2 real roots when B² - 4AC > 0.

So, px² - 2x + 3 = 0 has 2 real roots when (-2)² - 4(p)(3) = 0

-12p = -4

p = 1/3