
Francisco P. answered 10/22/14
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Rigorous Physics Tutoring
Assume the origin to be the center of the disk. We will weigh the distance by the mass: dm = ρdA with dA = 2πrdr, a thin ring around the origin. Let ρ = M/πa2 where M is the mass of the disk.
ravg = 1/M ∫rρ(2πr)dr integrated from 0 to a.
ravg = (2πρ/M) ∫r2 dr = (2πρ/M) [(1/3) r3] from 0 to a.
ravg = (2π/M)(M/πa2)(a3/3) = 2a/3