x4 + x2 - 72 = 0
Let u = x2, so u2 = x4
x4 + x2 - 72 = 0
u2 + u - 72 = 0
(u+9)(u-8) = 0
u = -9 and 8
u = x2 = -9
x = +/- 3i
u = x2 = 8
x = +/- sqrt(8) = +/- 2sqrt(2)
4 zeros at x = +/- 3i and +/- 2sqrt(2)
Alesha V.
asked 10/25/18Find all zeros of this equation: x^4 +x^2 -72 =0.
x4 + x2 - 72 = 0
Let u = x2, so u2 = x4
x4 + x2 - 72 = 0
u2 + u - 72 = 0
(u+9)(u-8) = 0
u = -9 and 8
u = x2 = -9
x = +/- 3i
u = x2 = 8
x = +/- sqrt(8) = +/- 2sqrt(2)
4 zeros at x = +/- 3i and +/- 2sqrt(2)
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