Suppose that y varies inversely as the square of x, and that y=9 when x=19. What is y when x=17? (Round off your answer to 2 decimal places.)

Answer 1

y = k / x^2

9 = k / 19^2 = k / 361

k = 9(361) = 3249

y = 3249 / x^2

For x = 17,

y = 3249 / 17^2 = ?