Let L = length, W = width and P = perimeter
L = 3W + 6
P = 2(L + W) = 396
3W + 6 + W = 198
4W = 192
W = 48
L = 150
Destiny L.
asked • 10/18/18The length of a new rectangular playing field is 6 yards longer than triple the width. If the perimeter of the rectangular playing field is 396 yards, what are its dimensions?
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