lengthofarectangleis6ftlongerthan2xitswidthfindperimeterintermsofitswidthalone

Question

The length of a rectangle is 6 feet longer than 2 times its width.

Find the perimeter of the rectangle in terms of its width alone

Answer 1

We're dealing with a rectangle, and specifically the perimeter of the rectangle.  This formula is P = 2*l + 2*w.  The problem states that the length of the rectangle is 6 feet longer than 2 times the width.  If we translate this part of the word problem, we get

 

l = 6 + 2*w

 

Plug this formula in for l in the original formula and you get P = 2*(6 + 2*w) + 2*w, which simplifies to

 

P = 12 + 6*w