
Russ P. answered 10/11/14
Tutor
4.9
(135)
Patient MIT Grad For Math and Science Tutoring
Alexis,
You have a contradiction in the way you wrote your problem twice in that the < gets flipped to >. I'll solve both and you pick the correct one.
(1) (2x + 3) < (6x + 7/3)
(2x + 9/3) < (6x + 7/3), now just move constants to the left side and the x terms to the right side
(9/3 - 7/3) < (6x - 2x) , combine. simplify and solve the inequality
2/3 < 4x
1/6 < x , or all x > 1/6 is the solution here
(2) (2x + 3) > (6x + 7/3)
(2x + 9/3) > (6x + 7/3), now just move constants to the left side and the x terms to the right side
(9/3 - 7/3) > (6x - 2x) , combine. simplify and solve the inequality
2/3 > 4x
1/6 > x , or all x < 1/6 is the solution here
(2x + 9/3) > (6x + 7/3), now just move constants to the left side and the x terms to the right side
(9/3 - 7/3) > (6x - 2x) , combine. simplify and solve the inequality
2/3 > 4x
1/6 > x , or all x < 1/6 is the solution here