
Francisco P. answered 10/09/14
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Rigorous Physics Tutoring
The rectangle will have a diagonal that is the diameter of the circle.
x2 + y2 = c2 = 64
A = xy
y = √(64 - x2)
A = x√(64 - x2)
The value to maximize A satisfies 0 < x < 8. At this point you can plot this function and see the solution.
Here take the derivative and set it to zero.
dA/dx = -x2/√(64-x2) + √(64-x2)
dA/dx = 0:
x2 = 64 - x2 or x2 = 32
x = 4√2
So, y = 4√2.
The rectangle is a square and its area is (4√2)(4√2) = 32.