one train leaves at 1:45pm another leaves at 1:55 pm the first one travels 45k/h the second travels 55k/h when do they meet

Question

I need help with this ASAP or I will get suspended 

Answer 1

When train 2 leaves, train 1 will have already gone 45/6 = 7.5k

 

45t + 7.5 = 55t

10t = 7.5

t = 0.75

 

0.75(60) = 45

 

They will meet 45 mins after train 2 leaves, so 2:40.

 

Let's check.

 

0.75(55) = 41.25k

 

Train 1 will have travelled 55 mins, or 11/12 of an hour.

 

(11/12)45 = 41.25