Lauren H. answered • 10/03/18
Tutor
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Experienced High School Chemistry Teacher
One leg of a right triangle is 3 inches more than twice the length of the other leg
L = 2l + 3
The hypotenuse is 9 inches more than the shorter leg
h = l + 9
l^2 + L^2 = h^2
l^2 + (2l + 3)^2 = (l + 9)^2
l^2 + 4l^2 + 12l + 9 = l^2 + 18l + 81
4l^2 + 12l + 9 = 18l + 81
4l^2 - 6l - 72 = 0
l = 5.06
L = 13.12
h = 14.06
