One leg of a right triangle is 3 inches more than twice the length of the other leg

Question

One leg of a right triangle is 3 inches more than twice the length of the other leg. The hypotenuse is 9 inches more than the shorter leg. Find the lengths of all sides

Answer 1

One leg of a right triangle is 3 inches more than twice the length of the other leg

L = 2l + 3

The hypotenuse is 9 inches more than the shorter leg

h = l +  9

l^2 + L^2 = h^2

l^2 + (2l + 3)^2 = (l + 9)^2

l^2 + 4l^2 + 12l + 9 = l^2 + 18l + 81

4l^2 + 12l + 9 = 18l + 81

4l^2 - 6l  - 72 = 0

l = 5.06

L = 13.12

h = 14.06