line through the origin and perpendicular to y=-3x+6

Question

line through the origin and perpendicular to y=-3x+6

Answer 1

y = mx + b

 

The slope must be the negative reciprocal of the given slope, so

 

m = -1/-3 = 1/3

 

y = (1/3)x + b

 

Use the origin to find b.

 

0 = (1/3)(0) + b

 

b = 0

 

y = x/3

 

Test the answer.