I’m not sure if I’m supposed to distribute

Question

3(x+1)- 4(y-1) =13

5(x+2)+ 2(y+3)= 0

Answer 1

Yes

 

3x + 3 - 4y + 4  = 13

 

5x + 10 - 2y - 6 = 0

 

 

 

3x - 4y + 7 = 13

5x - 2y +4 = 0

 

3x - 4y = 6

5x - 2y = -4

 

 

-7x = 14

 

x=-2

y=-3

 

CHECK:

3(-2 + 1 ) - 4(-3 - 1) = 3(-1) - 4(-4) = -3 + 16 = 13

 

5(-2+2) + 3(-3+3) = 0