Greg C. answered 09/29/14
Tutor
4.8
(13)
Detailed Integrated Algebra Test Prep, SHSAT, TACHS
For another approach re the first one, using the y-intercept form:
y = mx + b
We know m (the slope) is 2/3
We also know one set of x/y pairs since we're given (3,-1)
So, substituting, we get:
y = m*x + b
-1 = 2/3*(3) + b
-1 = 2 + b
-1 - 2 = b
-3 = b
Now that we have b, and were given m, we get:
y = m*x + b
y = 2/3*x - 3
y = mx + b
We know m (the slope) is 2/3
We also know one set of x/y pairs since we're given (3,-1)
So, substituting, we get:
y = m*x + b
-1 = 2/3*(3) + b
-1 = 2 + b
-1 - 2 = b
-3 = b
Now that we have b, and were given m, we get:
y = m*x + b
y = 2/3*x - 3
- Greg, from Queens, nearby Brooklyn
Cynthia P.
09/29/14