Finding the lengths of the sides of a triangle

Question

One leg of a right triangle is 66 millimeter shorter than the longer leg and the hypotenuse is 66 millimeters longer than the longer leg. Find the lengths of the sides of the triangle.

Answer 1

s² + (s - 66)² = (s + 66)²

s² + s² - 132s + 4356 = s² + 132s + 4356

s² - 264s = 0

s(s - 264) = 0

 

s = 0

Of course not, so we disregard.

 

s - 264 = 0

s = 264

 

264 - 66 = 198

264 + 66 = 330