sin2Theta+ sqrt3 costheta=0

Question

Solve for the angle theta when its between 0 and 2pi

Answer 1

sin(2θ) + √3cosθ = 0

 

2sinθcosθ + √3cosθ = 0

 

cosθ(2sinθ + √3) = 0

 

cosθ = 0 or sinθ = -√3/2

 

cosθ = 0 when θ = π/2 or 3π/2

 

sinθ = -√3/2 when θ = 4π/3 or 5π/3