Find standard form for a point that goes through (-1,2) and is parallel to y=-3x+7

Question

the point the line passes through is (-1,2) and out is parallel to y=-3x+7, I need the standard form. 

Answer 1

Hello Danialla

 

Finally an Algebra problem... 

 

First of all, if two lines are parallel then the lines have the same slope.  Since you want a line that is parallel to           y= -3x+7, I am going to use -3 as the slope for the other line. So m= -3 and passes thru (-1,2)

 

I am going to write this information into the POINT SLOPE FORM:  y-y1= m( x-x1).  Remember that (-1, -2) are (x1,y1).  So all you have to do next is plug in (x1,y1) and m into the point-slope formula.

 

y-2 = -3[x-(-1)]

y-2    = -3(x+1)             Subtracting a negative is just like adding

y-2    = -3x -3               Using the Distributive Property

   +3x     +3x                  Adding 3x to both sides

3x+y-2= -3                     Adding  2 from both sides

         +2   +2  

     3x+y =-1                     This is the Standard Form

 

There you have it.  Glad to be of help :)

 

D.Y. Taylor