The sum of twice an integer and 3 times the next consecutive integer is 48

Question

I have no idea what to do 

Answer 1

Let N = the integer 

Let N+1 = the next consecutive integer. 

 

The the above statements established, you can write the equation as follow: 

 

2N+3(N+1)=48

 

From here you can solve the equation for N to figure out what the number is. 

 

2N+3N+3=48

5N+3=48

5N=45

N=9

 

I hope this helps.